Pada segitiga ABC yang siku- siku di B berlaku sin A = 3/5. Jika BC= 6 cm, maka panjang sisi AB adalah.... O a. 12 cm O b. 11 cm O c. 10 cm O d. 9 cm O e. 8 cm
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Jawaban:
O c. 10 cm
Penjelasan:
Sin A = BC/AC = 3/5
AB = √AC²-BC²
= √5²-3²
= √25-9
= √16
= 4
BC = 3a → 3a = 6 → a = 2
maka,
AB = 4a = 4(2) = 8cm
AC = 5a = 5(2) = 10cm
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semoga bermanfaat
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